# -*- coding: utf-8 -*-
"""
Løsning av 2. grads likning

Created on Sat Jun 15 12:12:51 2019

@author: finnh
"""

import numpy as np


def fun_losn_2grads_likn(a, b, c):
    x1 = (-b + np.sqrt(b*b - 4*a*c))/(2*a)
    x2 = (-b - np.sqrt(b*b - 4*a*c))/(2*a)
    return (x1, x2)


a = 1
b = 0
c = 4

(x1, x2) = fun_losn_2grads_likn(a, b, c)
print('x1 =', x1)
print('x2= ', x2)